// return the sum of the first n even numbers recursively. Assume n > 0
function firstEvenNumbersSum(n) {
if (n === 0) {
return 0;
}
let num = (n * 2);
let sum = num + firstEvenNumbersSum(n-1)
return sum;
}
Here is what the above code is Doing:
1. If n is 0, return 0
2. If n is not 0, multiply n by 2 to get the next even number
3. Add that number to the sum of the first n-1 even numbers
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