# the sum of all first n natural numbers js

// return the sum of the first n even numbers recursively. Assume n > 0 function firstEvenNumbersSum(n) { if (n === 0) { return 0; } let num = (n * 2); let sum = num + firstEvenNumbersSum(n-1) return sum; }

**Here is what the above code is Doing:**

1. If n is 0, return 0

2. If n is not 0, multiply n by 2 to get the next even number

3. Add that number to the sum of the first n-1 even numbers